(6x^2+8x+1)/(2x+3)

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Solution for (6x^2+8x+1)/(2x+3) equation:


D( x )

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x in (-oo:-3/2) U (-3/2:+oo)

(6*x^2+8*x+1)/(2*x+3) = 0

6*x^2+8*x+1 = 0

6*x^2+8*x+1 = 0

DELTA = 8^2-(1*4*6)

DELTA = 40

DELTA > 0

x = (40^(1/2)-8)/(2*6) or x = (-40^(1/2)-8)/(2*6)

x = (2*10^(1/2)-8)/12 or x = (-2*10^(1/2)-8)/12

(x-((-2*10^(1/2)-8)/12))*(x-((2*10^(1/2)-8)/12)) = 0

((x-((-2*10^(1/2)-8)/12))*(x-((2*10^(1/2)-8)/12)))/(2*x+3) = 0

( x-((-2*10^(1/2)-8)/12) )

x-((-2*10^(1/2)-8)/12) = 0 // + (-2*10^(1/2)-8)/12

x = (-2*10^(1/2)-8)/12

( x-((2*10^(1/2)-8)/12) )

x-((2*10^(1/2)-8)/12) = 0 // + (2*10^(1/2)-8)/12

x = (2*10^(1/2)-8)/12

x in { (-2*10^(1/2)-8)/12, (2*10^(1/2)-8)/12 }

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